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Which type of decay converts`"_3^8 Li` to `"_4^8 Be`?
- alpha decay
- beta decay
- gamma decay
- none of these
- N/A
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Answer: B Explanation: -
An increase in atomic number results by which type of radioactive decay?
- alpha decay
- beta decay
- gamma decay
- none of these
- N/A
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Answer: B Explanation: -
Which one is the result of electron capture?
- a positron is formed
- gamma rays are emitted
- a neutron is formed
- an alpha-particle is formed
- N/A
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Answer: C Explanation: -
Naturally occuring non-radioactive nuclides most commonly contain which combination of the number of protons and the number of neutrons?
- odd protons, even neutrons
- even protons, even neutrons
- odd protons, odd neutrons
- even protons, odd neutrons
- N/A
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Answer: B Explanation: -
The spontaneous transformation of one nucleus into another occurs only if:
- the process results in a neutron/proton ratio of 1.0 in the products
- the process is endothermic
- the combined mass of products is less than the mass of the original nuclide
- sufficient energy is absorbed from the surroundings to derive the process
- N/A
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Answer: C Explanation: -
When Xe-123 emits a gamma ray, what will be the product?
`"_53^123I`
`"_55^123Cs`
`"_52^119Te`
`"_54^123Xe`
The atomic number and atomic mass remains unchanged during gamma ray emission.
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Answer: D Explanation: -
In the following nuclear reaction which particle is missing; `"_13^27 Al` + ? → `"_0^1 n` + `"_15^30 P`
alpha
beta
gamma
proton
`"_13^27 Al` + `"_2^4 He` `to` `"_0^1 n` + `"_15^30 P`
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Answer: A Explanation: -
Which particle is produced when P-29 decays to Si-29?
- alpha
- beta
- gamma
- positron
- N/A
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Answer: D Explanation: -
Which isotope on bombardment with a neutron produces Au-198 and a proton?
`"_80^197Hg`
`"_80^198Hg`
`"_81^199Tl`
`"_78^197Pt`
`"_80^198Hg` + `"_0^1 n` → `"_79^198 Au` + `"_1^1H`
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Answer: B Explanation: -
In the following nuclear equation select the missing particle: `"_12^24 Mg` + `"_1^2 H` `to` `"_2^4 He` + ?
`"_13^26 Al`
`"_13^22 Al`
`"_11^22 Na`
`"_10^20 Ne`
`"_12^24 Mg` + `"_1^2 H``to``"_2^4 He` + `"_11^22 Na`
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Answer: C Explanation: