Chapter No 4 :Nuclear Chemistry (220 MCQ`S)

  1. What will be the product after beta-decay of `"_64^159 Gd` ?

    1. `"_64^159 Gd`

    2. `"_65^159 Tb`

    3. `"_63^159 Eu`

    4. `"_62^155 Sm`

    5. Show Answer
      Answer: B
      Explanation:
      • `"_64^159 Gd``to``"_65^159 Tb` + _`"_1^0 e`

  2. What will be the product when Zn-73 decays by beta emission?

    1. `"_29^74 Cu`

    2. `"_29^73 Cu`

    3. `"_30^72 Zn`

    4. `"_31^73 Ga`

    5. Show Answer
      Answer: D
      Explanation:
      • `"_30^73 Zn``to``"_31^73 Ga` + _`"_1^0 e`

  3. What is the product formed by alpha-decay of Rn-220?
    1. Rn-220
    2. Rn-216
    3. Po-216
    4. Ra-224
    5. Show Answer
      Answer: C
      Explanation:
      • Mass number decreases by 4 and atomic number decreases by 2 units after emission of alpha-particle.
  4. When `"_13^27 Al` is bobmarded by an alpha-particle, one of the product is a proton and the other nuclide is:

    1. `"_12^27 Mg`

    2. `"_13^31 Al`

    3. `"_16^31 S`

    4. `"_14^30 Si`

    5. Show Answer
      Answer: D
      Explanation:
      • `"_13^27 Al` + `"_2^4 He``to``"_14^30 Si` + `"_1^1H`

  5. The nucleus of an atom of I-131 which is used in thyroid imaging consists of:
    1. 53 protons and 78 neutrons
    2. 53 protons and 75 neutrons
    3. 53 electrons and 78 protons
    4. 53 neutrons and 78 protons
    5. Show Answer
      Answer: A
      Explanation:
      • Atmoic number (i.e number of protons) of iodine = 53 and mass number = 131, thus number of neutrons = 131 - 53 = 78
  6. What nuclide will be formed after positron emission from `"_7^12 N`?

    1. `"_6^13 C`

    2. `"_7^11 N`

    3. `"_6^12 C`

    4. `"_8^12 O`

    5. Show Answer
      Answer: C
      Explanation:
      • `"_7^12 N``to``"_6^12 C` + `"_1^0 e`

  7. When `"_90^232 Th` undergoes a series of alpha and beta-emissions, the final stable product is `"_82^208 Pb`. How many alpha and beta-emissions occur in this series?

    1. 6 alpha, 6 beta

    2. 6 alpha, 4 beta

    3. 8 alpha, 6 beta

    4. 4 alpha, 6 beta

    5. Show Answer
      Answer: B
      Explanation:
      • Decrease in mass number of product = 232 - 208 = 24 , thus no. of alpha emissions = 24/4 = 6 (Since alpha emission decreases mass number by 4 and atomic number by 2 units). During 6 alpha-emissions decrease in atomice number = 6 x 2 = 12. Observed decrease in atomic number = 90 - 82 = 8 , thus number of beta-emissions = 12 - 8 = 4 (Since each beta-emission increase the atomic number by one unit while the mass number remains unchanged)

  8. Which product is formed by positron emission of `"_84^207 Po`:

    1. `"_83^207 Bi`

    2. `"_83^206 Bi`

    3. `"_82^203 Pb`

    4. `"_85^208 At`

    5. Show Answer
      Answer: A
      Explanation:
      • By positron (`"_1^0 e`) emission, the atomic number decreases by one and the mass number remains unchanged.

  9. Which statement is false about the biological effects of radiation?
    1. radon is absorbed through skin
    2. radiation can cause leukemia
    3. radon is harmful because it decays to polonium
    4. ionizing radiation is more dangerous than non-ionizing radiation.
    5. Show Answer
      Answer: A
      Explanation:
      • N/A
  10. What product is formed when Ac-222 emits an alpha-particle?
    1. Ra-218
    2. Fr-218
    3. Db-218
    4. Ac-218
    5. Show Answer
      Answer: B
      Explanation:
      • N/A

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